The sum of four consecutive intergers is 8 what are the intergers

Consecutive integers are 1 apart
so the 4 are
x, x+1,x+2,x+3

they add to 8

x+x+1+x+2+x+3=8
4x+6=8
minus 6 both sides
4x=2
divide both sides by 4
x=1/2
false, 1/2 is not an integer

if it was adding to 18, then the integers would be 3,4,5,6
but we can't find consecutive integers that add to 8

128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3

Ithink ghe answer to this question is b just trying to others