If you subtract the least integer from the greatest integer and divide the difference by 3 the quotient is 5

Let a and b be integers and b>a, then we can say:

(b-a)/3=5  now multiply both sides by 3

b-a=15

b=15+a

So there are infinitely many pairs of integers that satisfy the conditions given in the problem. For any value a, b will be 15 units greater.

You just need to add 32 to 14 and get 46.

The answer would be b