Based on the graph, what is the initial value of the linear relationship? a coordinate plane is shown. a line passes through the y axis at 4 and the x axis at 5.

a. negative four over five
b. 0
c. 4
d. 5

Option: C is the correct answer.

C. 4

Step-by-step explanation:

The initial value of a linear function or an linear equation is the y-intercept of the function which is also known as the value of y i.e. the output value where the input value i.e. the value of x is zero.

As we are given that the line passes through the y-axis at 4 this means that the y-intercept of the given linear graph is (0,4).

Hence, the initial value of the given linear relationship is:

4

answer: standard form is ax^2 + bx + c = 0

step-by-step explanation:

standard form is ax^2 + bx + c = 0

(2x + 1)(x - 2) = 0

distribute to get into standard form

2x^2 - 4x + x - 2 = 0

2x^2 - 3x - 2 = 0

a = 2, b= -3, c = -2

a is your answer

y= 2x+7

changed to y= 5x +7

as slope is increased from 2 to 5

therefore it would be less steeper

so, option d) is correct