Eli has 7 black pens and 5 blue pens in his desk drawer. he also has 3 yellow highlighters, 2 green highlighters, and 5 pink highlighters in his pencil case. if he chooses one pen and one highlighter without looking, what is the probability that he will get a black pen and he will not get a green highlighter?
2/22 or 9% chance he will not get a green highlighter
The probability is 7/15.
Total number of pens = 7+5 = 12
Out of 12, 7 are black and 5 are blue pens.
Similarly, total number of highlighters = 3+2+5 = 10
Out of 10, 3 are yellow highlighters, 2 are green highlighters, and 5 are pink .
Now, Eli is choosing one pen and one highlighter without looking, so the probability that he will get a black pen and he will not get a green highlighter will be =
Hence, the probability is 7/15 or 46.66%.
I m not 100% sure, but I think it is correct...
a 10 percent increase
took the test it's 94