The vertices a(–2, –1), b(–3, 2), c(–1, 3), and d(0, 0) form a parallelogram. the vertices a’(–1, –2), b’(2, –3), c’(3, –1), and d’(0, 0) are the image of the parallelogram after a sequence of transformations. which sequence of transformations could produce the image from the pre-image?

Solution:

Vertices of Preimage  i.e the shape which is a parallelogram=A(–2, –1), B(–3, 2), C(–1, 3), and D(0, 0)

A transformation is done on the Preimage to get image

Vertices of image  i.e the shape which is a parallelogram=A’(–1, –2), B’(2, –3), C’(3, –1), and D’(0, 0)

Reflection along a line(Mirror) has taken place , the reason being that the points are inverted i.e (a,b) is replaced by (b,a).

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19

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