Which statement is true about anja’s claim?
she is incorrect; the histogram is skewed to the left because more data is on the left side.
she is incorrect; the histogram is skewed to the left because there is more data on the right side.
she is incorrect; the histogram is symmetrical because the right side is equal to the left side.
she is correct; the histogram is skewed to the right because there is less data on the right side.

answer with explanation:

when a curve is a bell shaped curve,following thing can happen

→when most of the variate of the data set is   on the left side of that is when you draw the curve, tail expansion is more on the left, the curve of normal distribution, will be skewed to left.

mean < median< mode

→similarly, when most of the variate of the data set is   on the right side side tail of the curve is on the right of the curve, the curve of normal distribution will be skewed to right.

mean> median> mode

→when, data set is symmetrical, that is equally distributed on both side

in this type of distribution , mean = median =mode

option c: she is incorrect; the histogram is symmetrical because the right side is equal to the left side.

a4 - 3a2 - 1

step-by-step explanation:

step   1   :

equation at the end of step   1   :

  ((a4) -   3a2) -   1

step   2   :

trying to factor by splitting the middle term

2.1     factoring   a4-3a2-1  

the first term is,   a4   its coefficient is   1 .

the middle term is,   -3a2   its coefficient is   -3 .

the last term, "the constant", is   -1  

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this