An integer is chosen at random from the first 40 positive integers. what is the probability that the integer chosen is divisible by 6 or 8?

1/4

Step-by-step explanation:

There are 40/8 = 5 integers in the range that are divisible by 8. There are floor(40/6) = 6 integers in the range that are divisible by 6. Of those sets of integers, one (24) is divisble by both numbers. So, altogether, there are 5+6-1 = 10 of the 40 integers that are divisible by 6 or 8.

If you choose an integer at random from the range 1–40, the probability is 10/40 = 1/4 that it will be divisible by 6 or 8.

is there any photos or whatever?

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

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