Find the x-intercepts of the parabola with vertex (1, -9) and y intercept at (0, -6).

hello :
the parabola's equation is : f(x) = a(x-1)²-9
the coefficient of the squared expression in the parabola's equation is : a
but ; f(0) = -6 ...  ( y-intercepts (0,-6) )

-6 = a(0-1)²-9
-6 =a -9

a=3
f(x) = 3(x-1)²-9

omg what happend to your question? if you could edit this question i can

step-by-step explanation: