Saturn orbits the sun at a distance of 1.43 × 1012 m. the mass of the sun is 1.99 × 1030 kg.
use to determine saturn’s orbital period in earth years. is it:
a)29.6 earth years
b)296 earth years
c)874 earth years

Saturn’s orbital period is 29.6 years

Step-by-step explanation:

It is given that,

The mass of the sun, m = 1.99 × 10³⁰ kg

Saturn orbits the sun at a distance of, a = 1.43 × 10¹² m

Using third law of Kepler's :

Where,

T is the orbital time period

G is the universal gravitational constant

M is the mass of the sun

a is the distance

So,

To convert seconds into year divide the time by 3.154 × 10⁷

So, T = 29.55 Years

or T = 29.6 Years

Hence, the Saturn's orbital period is 29.6 Earth years       

total amount to be paid = $19.5

step-by-step explanation:

given ,

original price = $25.99

discount = 25%

discount amount = 25% of original price

discount amount = 25/100   * 25.99

discount amount = $6.49

hence , the total amount to be paid = original price - discount amount

                                                            = $25.99 - $6.49

                                                            =$19.5

total amount to be paid = $19.5

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)