Mathematics
Mathematics, 25.08.2019 06:30, FreyaLouise

The radius of the base of a right circular cone is 6 and the radius of a parallel cross section is 4. if the distance between the base and the cross section is 8, what is the height of the cone?
a. 11
b. 13 1/3
c. 16
d. 20
e. 24

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Mathematics, 22.06.2019 01:00, SpeechlessZzz9920
For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)
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Mathematics, 27.06.2019 12:20, alandrabell9234
Hey i'm failing and really need , all effort is appreciated : ) drag and drop an answer to each box to correctly complete the explanation for deriving the formula for the volume of a sphere. for every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius r and height 2r minus the volume of two cones, each with a radius and height of a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is , and the volume of each cone with radius r and height r is 13πr3 . so the volume of the cylinder minus the two cones is 43πr3 . therefore, the volume of the cylinder is by cavalieri's principle.
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Mathematics, 29.06.2019 16:30, hijdjdjdbdjidjdbdbd
For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)
Answers: 1
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