Suppose you flip a coin and roll a number cube. what is the probability of having tails come up on the coin and an even number on the number cube?

Assuming a fair coin and a fair 6-sided die.

Coin has 2 sides with equal probability, 50% each.

Die has 6 sides with equal probability, 1/6 odds for each side.

Odds of heads = 1/2.

Odds of die rolling 5 or greater (5 or 6) = 2/6.

The probability of both things happening is the multiplication of the probability of the two happening separately, or (1/2)*(2/6) = 1/6.

 The required probability is 25%.

Step-by-step explanation:  Given that a coin is flipped and a number cube is rolled.

We are to find the probability of getting a tail on the coin and an even number on the number cube.

The sample space for flipping a coin and rolling a number cube is given by

S = {H1, H2, H3, H4, H5, H6, T1, T2, T3, T4, T5, T6}

⇒  n(S) = 12.

Let A denote the event of getting tail and an even number.

Then, A = {T2, T4, T6}

⇒ n(A) = 3.

Therefore, the probability of event A is given by

Thus, the required probability is 25%.

.bjbjk.b,j.l.

step-by-step explanation:

hello :

by applying the distributive property :

6 × 4.3 = 6 × ( 4 + 0.3 )

            =   (6 ×   4) + (6 ×   0.3)

            = 24 + 1.8

6 × 4.3 = 25.8