Δabc is a right triangle in which is a right angle, ab = 1, ac = 2, and bc = .

cos c × sin a =

Step-by-step explanation:

Given a right triangle ABC where AB = 1, AC = 2

As it is a right triangle, thus by Pythagoras theorem

Now ,

as

and

Therefore,

Cos C × Sin A =   and BC = √3.

Step-by-step explanation:

Given :  A right triangle ABC where AB = 1, AC = 2 .

To Find  : BC and cos C × sin A .

Solution :We have ΔABC is a right triangle, AB = 1, AC = 2.

As it is a right triangle, thus by Pythagoras theorem

AC² = AB² +BC².

2² = 1² + BC²

4 = 1 + BC²

BC = √3.

Now ,

Sin A =

Sin A = .

Sin A = .

Cos C =  .

Cos C = .

Cos C = = .

Cos C × Sin A

×.

⇒ .

Therefore, Cos C × Sin A =   and BC = √3.

throw the computer

step-by-step explanation:

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step-by-step explanation:

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