Determine the coordinates of the vertex and horizontal intercepts of the parabola. (if an answer does not exist, enter dne.)
f(x) = −7(x + 12)2 + 14
i cant figure out the horizontal intercepts.

f(x) = −7(x + 12)² + 14
 the coordinates of the vertex are (-12;14)
  f(x)=-7(x²+24x-144)+14
f(x)=-7x²-168x+1008+14
f(x)=-7x²-168x+1022=0
7x²+168x-1022=0
x====-12+-√290
x₁=-12-√290
x₂=-12+√290
the coordinates of the vertex are (-12;14),
horizontal intercepts are x₁=-12-√290, x₂=-12+√290

A)26•2=52there are 2 sides with the same length116-52=64the other 2 side have to be half of 64 each64/2=32the width is 32b)make two sentences about these steps because your teacher knows how you write and explain things.

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