Connor wants to use the fermi process to estimate the number of oranges that would fill his kitchen. as part of the process, he needs to estimate the volume of a typical orange. the diameter of an orange is about 3 in.

which estimate best approximates the volume of the orange?

1×10^0 in³
1×10^1 in³
1×10^2 in³
1×10^3 in³

Given:
diameter of an orange is 3 inches

Volume of a sphere = 4/3 * π * r³

V = 4/3 * 3.14 * (1.5in)³
V = 4/3 * 3.14 * 3.375
V = 14.13 in³  This is the actual volume of an orange

Let us simply solve the given choices to choose which is the nearest approximate:

1×10⁰ in³ → 1 x 1 in³ = 1 in³
1×10¹ in³ → 1 x 10 in³ = 10 in³
1×10² in³ → 1 x 100 in³ = 100 in³
1×10³ in³ → 1 x 1000 in³ = 1000 in³

10 in³ is closest to 14.13 in³. So, the best approximate is 1 x 10¹ in³

No he does not because he can only cover 12 square feet from 15 square feet which he will still need 3 more. this is because if 3×5=15 square feet and 15-12=3 which thats the answer