Suppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i. e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 in each case.

The angles with respect the positive x-axis are given by the following formulas for each quadrant.

Second quadrant

Third quadrant

Fourth quadrant

Step-by-step explanation:

In order to calculate the angle in a general way, we always use the formula

That will give us the angle of the associated reference triangle, the issue is that the the output of the inverse trigonometric function is in the range and that does not give us the exact angle with respect the positive x-axis.

Thus we need to add some angle to get the correct angle with respect the positive x-axis.

Case second quadrant.

The output of will be negative, since y is greater than 0 but x is less than zero.

To fix that, and get the angle on the second quadrant we can add either pi  or 180 degrees, so we will get:

Case third quadrant.

The output of will be positive but it will be smaller than 90 degrees.

To fix that, and get the angle on the second quadrant we can add either pi  or 180 degrees, so we will get:

Case fourth quadrant

The output of will be negative since y is less than 0 but x is positive.

To fix that we can get a positive coterminal angle, that means adding 2pi or 360 degrees, so we will get

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet