![\displaystyle\int_{.5}^1\frac{1}x\frac{dx}{x^3}=\int_{.5}^1\frac{dx}{x^4}=\left[\frac{-1}{3x^3}\right]_{.5}^1=\frac{7}3](/tpl/images/0178/9297/a7c29.png)
What is the result?
∫([1/x].dx/x^3)
d=[1/2, 1]...
Answers: 1
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