![\bf f(x)=\cfrac{sin(x)}{x^2}\implies \cfrac{dy}{dx}=\cfrac{x^2cos(x)-2xsin(x)}{(x^2)^2} \\\\\\ \cfrac{dy}{dx}=\cfrac{x[xcos(x)-2sin(x)]}{x^4}\implies \cfrac{dy}{dx}=\cfrac{xcos(x)-2sin(x)}{x^3} \\\\ -----------------------------\\\\](/tpl/images/0336/7288/37619.png)
![\bf f(x)=(3x^2+2x-1)^4\implies \cfrac{dy}{dx}=4(3x^2+2x-1)^3(6x+2) \\\\ -----------------------------\\\\ f(x)=\left( \cfrac{x-5}{2x+1} \right)^2\implies \cfrac{dy}{dx}=2\left( \cfrac{x-5}{2x+1} \right)\left[ \cfrac{2x+1-2(x-5)}{(2x-1)^2} \right] \\\\\\ \cfrac{dy}{dx}=2\left( \cfrac{x-5}{2x+1} \right)\left[ \cfrac{11}{(2x-1)^2} \right]](/tpl/images/0336/7288/bb039.png)
Find f'(x) and simplify!
a) f(x)= sinx/(x^2)
b) f(x)= (3x^2 +2x -1)^4
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Mathematics, 20.10.2019 09:30, ChloeLiz9205
Find f'(x) and simplify!
a) f(x)= sinx/(x^2)
b) f(x)= (3x^2 +2x -1)^4
c) f(x)= (x-5/2x+1)^2
Answers: 2
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