Answers: 3
, V = (p,q)![f(x)=2x^2+6x-8\\\\\ f(x)=ax^2+bx+c\\\\ a=2 \ , \ b=6 \ , \ c=-8 \\\\ p=\frac{-b}{2a}=\frac{-6}{\not2* 2}=-\frac{3}{2}\\\\q=\frac{-\Delta}{4a}=\frac{-(b^2-4ac)}{4a}=\frac{-[6^2-4*2*(-8)]}{4*2}=\frac{-100}{8}=-\frac{25}{2}](/tpl/images/0329/9485/22a57.png)
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