Lisa richter deposited $5,000 at 4% compounded semiannually for three years. at the beginning of the fourth year, lisa deposited $2,500. what would her balance be at the end of five years assuming she is still earning 4% compounded semiannually?

$8,801.05

Step-by-step explanation:

Lisa Richter deposited $5,000 at 4% compounded semiannually for three years.

To calculate the amount after 3 years we use the formula

Where A = Future amount

           P = Principal amount ($5,000)

           r = rate of interest 4% (0.04)

           n = number of compounding interest semiannually (2)

           t = time (3 years)

Now put the values in the formula

A = 5000(1.126)

A = $5,630.81

At the beginning of the fourth year Lisa deposited $2,500. Now the amount would be

New principal amount = 5630.81 + 2500 = 8,130.81

we have to calculate the future amount at the end of five years or for 2 more years.

We will use the same method as we done above.

A = 8130.81 (1.08243)

A = $8,801.05

Lisa's balance at the end of five years $8,801.05

step-by-step explanation:

equation

you are asked to write the equation

  expression = 0

using the given expression. when you do that, you have

  2x^2-2x-12 = 0

factoring

you can see that each of the coefficients is even, so a factor of 2 can be removed immediately.

  2(x^2 -x -6) = 0

if you multiply the binomials (x+a)(x+b), you get

  (x +a)(x +b) = x^2 +(a+b)x +ab

this tells you the coefficient of x is the sum of two factors of the constant term. here, that means -1 is the sum of two factors of -6. we want to know those factors so we can factor the trinomial.

  -6 = -1×6 = -2×3 = -3×2 = -6×1

the factor pair that sums to -1 is {-3, 2}, so our factorization is

  2(x -3)(x +2) = 0

solutions

the solutions to this equation are the values of x that make the product zero. a product is zero only when only of the factors of the product is zero. here, that means

  x - 3 = 0

  x = 3 . . . add 3 to both sides of the equation

or

  x +2 = 0

  x = -2 . . . add -2 to both sides of the equation

the solutions to the equation are x=3 or x=-2. both of these values of x satisfy the equation—they make it be true.

the square root of what number? if you add that, then someone will probably answer the question.