Acoffee mixture contains beans that sell for $0.08 per pound and $0.32 per pound. if 110 pounds of beans create a mixture that sells for $0.27 per pound, to the nearest tenth of a pound, how much of each bean is used in the mixture? model the scenario with an equation and solve. use complete sentences to explain whether or not your solution is reasonable.

0.08x + 0.32(110 - x) = 0.27(110)

0.08x + 35.20 - 0.32x = 29.7

           -35.2                   -35.2

0.08x - 0.32x = -5.5

-0.24x = -5.5

/-0.24    /-0.24

x = 22.9 pounds of beans that sell for $0.08 per pound

110 - 22.9 = 87.1 pounds of beans that sell for $0.32 per pound

This is reasonable because the beans can be weighed to the nearest tenth.

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step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

step-by-step explanation:

for volume, add base x height x width