Aworker has four different job offers, each with a contract for six years. assuming the job descriptions are identical, which offer will allow the worker to earn the most over six years?

a starting salary of $49,000 with a 3% increase each year
a starting salary of $51,000 with a 1% increase each year
a starting salary of $48,000 with a 6% increase each year
a starting salary of $50,000 with a 2% increase each year

 $49,000 with a 3% increase each year
1st    49,000 x 12 = 588000
2nd  49,000 (.03)  = 49,000+1470=   50,470 (12 mos)= 605640
3rd   50,470(.03)  =   50470+1,514.1= 51,984.1 (12 mos)=623809.2
4th   51,984.1 (.03) =  51,984.1 +  1559.52 =53,543.62 (12)=642523.44
5th   53,543.62(.03)   = 53,543.62 + 1606.31= 55,149.93 (12)= 661799.16
6th    55,149.93(.03)   =55,149.93 + 1654.50=56804.43 (12)=681653.16

TOTAL =$3,803,425
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a starting salary of $51,000 with a 1% increase each year
1st    51,000 (12) =612000
2nd  51,000 (.01)  = 51,000+ 510=  51510 (12) = 618120
3rd  51510  (.01)  =   51510+ 515.1= 52,025.1 (12)= 624301.2
4th   52,025.1 (.01) =  52,025.1 +  520.251 = 52,545.351 (12) =630544.212
5th   52,545.351(.01)   = 52,545.351 + 525.45= 53,070.801 (12)=636849.612
6th    53,070.801(.01)   =53,070.801 + 530.708=53601.509=643218.108

TOTAL: $3,765,033.132

a starting salary of $48,000 with a 6% increase each year
1st    48,000
2nd  48,000 (.06)  = 48,000+ 2880=  50880 (12) =576000
3rd  50880  (.06)  =   50880+ 3052.8= 53,932.8 (12)= 610560
4th   53,932.8 (.06) =  53,932.8 +  3235.97 = 57,168.77 (12) =647193.6
5th   57,168.77 (.06)   = 57,168.77+ 3430.13 = 60598.9 (12)= 727186.8
6th    60598.9(.06)   =60598.9 + 3635.93=  64234.83 (12)=770817.96

TOTAL: $4,017,783.6

a starting salary of $50,000 with a 2% increase each year

1st    50000 (12)=600000
2nd  50000 (.02)  = 50000+ 1000=  51000 (12) = 612000
3rd  51000  (.02)  =   51000+ 1020= 52020 (12) =624240
4th   52020 (.02) =  52020 + 1040.4 = 53060.4=636724.8
5th   53060.4 (.02)   = 53060.4+ 1061.21 = 54121.61=649459.32
6th    54121.61(.02)   =54121.61 + 1082.43= 55204.04=662448.48
TOTAL $3,784,872.6


The answer is a starting salary of $48,000 with a 6% increase each year