The following table shows the time in various cities when it is 4: 00 a. m. in new york.
new york
4: 00 a. m.
san juan
5: 00 a. m.
buenos aires
6: 00 a. m.
dublin
9: 00 a. m.
rome
10: 00 a. m.
istanbul
11: 00 a. m.
saint petersburg
12: 00 p. m.
beijing
5: 00 p. m.
osaka
6: 00 p. m.
if a flight between two of these cities leaves at 1: 30 p. m. on friday (local time), flies for 16 hours and 30 minutes, and arrives at 2: 00 a. m. saturday (local time), which of the following pairs of cities could the flight go between?
a.
new york and rome
b.
saint petersburg and beijing
c.
dublin and san juan
d.
osaka and istanbul

The correct option is C

Step-by-step explanation:

Let the flight go between X and Y

Time at which flight leaves X is 1:30 p.m (local) and time at which flight arrives in Y is 2:00 a.m (local)

The time in city X when the flight arrives in Y = 1:30 p.m (friday) + 16 hours 30 minutes

= 6 a.m (saturday). But the local time of Y is given 2 a.m

So, the flight will go between those two cities where time in of first is 4 hours ahead of time in second

And according to options, C. is correct because when the time is 6 a.m. in Dublin the time in San Juan is 2 a.m which is our required cities X and Y

So, the flight will go between X and Y

here the number -5 is all of the following except a rational number.

step-by-step explanation:

correct answer:

i^31 = -i