Apilot flies in a straight path for 1 hour and 30 min. she then makes a course correction, heading 10 degrees to the right of her original course, and flies 2 hours in the new direction. if she maintains a constant speed of 640 miles per hour, how far is she from her starting position?

The first leg of the flight is (!.5 hr)(680 mph) = 1020 miles long.  Let's call this side b of our triangle.The second leg of the flight is (2 hr)(680 mph) = 1360 miles long. Let's call this side c of our triangle. We can find the length of side a of the triangle from the law of cosines.  The angle A between the two sides whose length we know is 170°. (180° - 10° = 170°). a2 = b2 + c2 - (2)*(a)*(b)*cos(A) a2 = (1020 miles)2 + (1360 miles)2 - (2)*(1020 miles)(1360 miles)*cos(170°) a2 = 1040400 miles2 + 1849600 miles2 - (2774400 miles2)*cos(170°) cos(170°) = -0.9848 a2 = 2890000 miles2 + 2732251 miles2 = 5622250.6 miles2 a = (5622250.6 miles2)½ = 2371 miles

29. because you will divide each number of months by 12 to find the number of years. which would mean, 5, 12.5, 16, 45, 50, 72.5. which is crazy. anyhow, i think you find the median in the middle. and yea hope your test goes good

Answers4.) -1/205.) -1/406.) -55/127.) -3/4