The sum of 6 consecutive integers is 393. what is the third number in this sequence?

So, let first be x

then , second be x+1
and so on

so the eqn will be,

x+x+1+x+2+x+3+x+4+x+5=393
6x= 393-15
x= 378/6
x= 63

so first no I 63
second will be 64

and third (your answer) will be 65 !!