Agroup of 10 fisherman enjoy certain types of fish, 3 of them like salmon, 5 like trout and 2 like bass. a single fisherman is chosen at random. what is the probability that the fisherman likes salmon or bass?
a. 1/10
b. 47/90
c. 3/50
d. 1/2

There are a total of 10 fishermen as stated in the given. The probability that a chosen fisherman liked salmon is 3/10. Also, the probability that a fisherman liked bass is 2/10. By using the conjunction "or" we add the probabilities of these events to arrive with the answer giving us 5/10 or 1/2. The answer is letter D. 

In all honesty, there really is no “work” per say to show. mainly it’s just using the process of elimination. the question is asking which domain(s) would be the most appropriate for the function c(n). n is the number of observed vehicles so right away, 1, 2, and 3 can be eliminated.why? 1, 2 start in the negatives and therefore it is impossible to observe negative cars. so, #4 would be the best answer to the given problem.