Aregular heptagon has a radius of approximately 27.87 cm and the length of each side is 24.18 cm. what is the approximate area of the heptagon rounded to the nearest whole number? recall that a heptagon is a polygon with 7 sides. 1,173 cm2 2,125 cm2 2,359 cm2 4,250 cm2

Answer-

The area of the heptagon will be 2125 cm²

Solution-

A regular heptagon is a combination of 7 equal isosceles triangles. So the area of the regular heptagon is equal to 7 times the area of the isosceles triangle.

From the attachment it can be followed that,

Base = 24.18 cm

Radius = 27.87 cm

Applying Pythagoras Theorem,

(As the perpendicular bisects the base in case of an isosceles triangle)

Then the area of the triangle is,

So, the area of the heptagon will be,

160

step-by-step explanation:

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step-by-step explanation: