Circle o has center (2,6), and passes through the point p (4,3) write the equation of the line that is tangent to circle o at point p

Circle equation :(y-k)² + (x-h)² = R², Given Center coordinates (2,6) =(h,k)

==> (y-2)² +(x-6)² - R²

Find R: Let P the point on the circle at (4,3) so R² = 4² + 3²=> R²= 25
SO THE FINAL EQUATION =>(y-2)² + (x-6)² =25