Answers: 1
![R1,R2=(-b+-sqrt(b^2-4.a.c)) / 2.a[tex] () Where a is the quadratic term coefficient, b is the linear term coefficient and is the independent term. By calculating the roots the factorized quadratic equation will be: [tex]a(x-R1)(x-R2)](/tpl/images/0269/5632/44c51.png)
![R1,R2=(-12+-sqrt(12^2-4.4.9)) / 2.4[tex] [tex]R1,R2=(-12+-sqrt(144-144)) / 2.4[tex] [tex]R1,R2=(-12+-sqrt(0)) / 8[tex] [tex]R1,R2=(-12)/8=-3/2[tex] Notice that -3/4 is R1 and R2, that is, the roots are equals. By replacing in the factorized form we have: [tex]4(x-(-3/2))(x-(-3/2))](/tpl/images/0269/5632/69cd0.png)
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