Use the data set to determine which statements are correct. check all that apply. 115, 120, 118, 104, 109, 148, 135, 141, 139

the median is 120.
the median is 109.
there is an outlier.
the lower quartile is 118.
the lower quartile is 112.
the upper quartile is 140.
the upper quartile is 141.
the interquartile range is 28.

Median=120

Lower quartile=112

upper quartile=140

interquartile range=28

Step-by-step explanation:

We find the median of a data by firstly arranging our data into ascending or descending order and then finding it's middle term.

on aaranging our data into ascending order we have:

104  109  115  118  120  135  139  141  148

hence we could clearly see that the middle term is 120.

Hence, Median=120.

the lower quartile is the median of a lower half of the data i.e. median of:

104   109   115   118

on calculating it's median we have lower quartile=112.

similarly upper quartile is the median of upper half of the data i.e. median of:

135   139   141   148

on calculating it's median we have upper quartile=140.

now interquartile range is the difference between upper quartile and lower quartile.

interquartile range=140-112

                               =28

Hence, interquartile range=28.

its d but looking at that hurts my eyes frfr

step-by-step explanation:

p = 6s

step-by-step explanation: