In two or more complete sentences, describe how the substitution method works for solving a two-order system of equations.

The first step is to set one of the equation equal to x or y. Then substitute this value into the other equation to find the value of the other variable. Finally, put the value obtained into the relation taken at the start.

Step-by-step explanation:

Let us consider an example,

3x + y = 8

x + y = 6.

The first step is to set one of the equation equal to x or y.

i.e. x = 6 - y.

Next step is to substitute this value into the other equation.

i.e. 3×(6-y) + y = 8

i.e. 18 - 3y + y = 8

i.e. -2y = -10

i.e. y = 5.

Finally, we put this value of y into the relation taken at the start

i.e. x = 6 - y

i.e. x = 6 - 10

i.e x = 4.

Hence, the solution of this system of equations using substitution method is (x, y) = ( 4, 5).

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?