There are 3 green balls, 5 red balls, and 2 blue balls in a box. one ball is randomly drawn, replaced and then another ball is drawn. what is the probability of getting a green ball then a blue ball? a. 1/15 b. ½ c. 3/100 d. 3/50 (show your work )

Option d. 3/50 is the correct option.

Step-by-step explanation:

Total number of balls given in a box is 10. Out of which different balls are

Green = 3, Red balls = 5, Blue = 2.

One ball was randomly drawn so probability of getting a green ball will be = 3/10

Now the ball was replaced so total number of balls remains the same

Then the probability of getting a blue will be = 2/10

Therefore the probability of both the events simultaneously = (3/10)×(2/10)=6/100 = 3/50

Option d. 3/50 is the answer.

0.85 or 85%

step-by-step explanation:

1) divide 23 by 27

2) round the decimal to the nearest 10

3) so your answer would be 0.85 or 85%

heyyy

step-by-step explanation: