How many pounds of nuts worth $1.10 per pound must be mixed with 36 pounds of candy worth $1.60 per pound to produce a party mix worth $1.50 per pound?

a. 9
b. 20
c. 114.5

9 pounds

Step-by-step explanation:

Let the amount of nuts be x

Cost of 1 pound nuts is $1.10

So, Cost of x pounds = $1.10 x

Cost of 1 pound of candy = $ 1.60

Cost of 36 pounds of candy =

So, total cost = 1.10 x + 57.6

Total weight = x+36

Cost of mixture per pound =

Now we are given that Cost of mixture per pound is $1.50

So,

Hence 9 pounds of nuts worth $1.10 per pound must be mixed with 36 pounds of candy worth $1.60 per pound to produce a party mix worth $1.50 per pound.

26?

step-by-step explanation:

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.