Addison painted her room. she had 50 square meters to paint, and she painted at a constant rate. after 2 hours of painting, she had 35 square meters left. let a(t), denote the area to paint a (measured in square meters) as a function of time t (measured in hours). answer !

The function can be determined by treating the two scenarios as two points since Addison paints at a constant rate. The equation can be obtained using the two-point form: (y-y1) = [(y2-y1)/(x2-x1)] (x-x1), where y refers to the area to be painted and x to the time elapsed. Substituting (x1, y1) as (0, 50) and (x2, y2), as (2, 35). The area to be painted is expressed as A(t) = -7.5t +50

Abit confused about what you mean, but i think you might be referring to slope intercept form: y = mx + bin that case b, or the y intercept is already given.(0,-1)find the slope by using the formulay2 - y1/x2 - x1the final slope will be 4/2, equivalent to 2.now your equation should look like thisy = 4/2x -1sorry if this didn’t you out!