Mathematics, 02.11.2019 05:31, pawfox
There are 12 people on a basketball team. how many different five-person starting lineups can be chosen
a)120
b)792
c)95,040
d)3,991,680
Answers: 1
![^{12}C_5=\frac{12!}{(12-5)!5!}............[^nC_r=\frac{n!}{(n-r)!r!}}]\\=\frac{12\times11\times10\times9\times8\times7!}{7!\times5!}\\\\=\frac{12\times11\times10\times9\times8}{120}=792](/tpl/images/0356/5922/22bce.png)
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There are 12 people on a basketball team. how many different five-person starting lineups can be cho...
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