Determine values of c and d for √which the equation √(3x-1) - √(cx + d) = 0 has no solution.
i added √(cx + d) to both sides and squared them..3x-1 = cx + d
rearranged to get 3x - cx = d + 1; then factored out x to get x(3 - c) = d + 1
then divided x = ( d + 1) / ( 3 - c) therefore c ≠ 3 what about d?
i'm not sure what question is asking when looking for c and d

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Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane