Let f(x)=20/1+9e^3x .

what are the asymptotes of the graph of f(x) ?

select each correct answer.

y = 3

y = 0

y = 9

y = 20

y = 0 and y = 20

Step-by-step explanation:

The given function is

There is no vertical asymptotes because the denominator will never be zero.

Horizontal asymptotes are given by

Take the constant 20 out of the limit

Now, we can further simplify as follows

Similarly, the second horizontal asymptote is

We can simplify this limit as we did the previous one

Hence, asymptotes of the graph of f(x) are

y = 0 and y = 20

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.