Simplify (8x^4)(4x^3) divided by 7x^2. a. 1/3x. b.32x^5/7. c.7/9x^4. d.1/28x

The rules for similar bases and different exponent needed for this problem...

(a^b)*(a^c)=a^(b+c) and (a^b)/(a^c)=a^(b-c)

[(8x^4)(4x^3)]/(7x^2)

(32x^7)/(7x^2)

(32x^5)/7

Yes you do, so £1973.09 - £1473.50 = £499.59 so tim overpaid £499.59 .hope this ; )

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

the value of x is equal to 0.