The number of visitors to a certain web site triples every month. the number of visitors is modeled by the expression 8100 times •3m, where m is the number of months after the number of visitors was measured. evaluate the expression for m=−33. what does the value of the expression represent in the situation?

Suppose we have had S visitors in n months since EIS (Entry Into Service) of the site, then : 
S(n) = 8100 + 8100 * 3 + 8100 * 3^2 + 8100 * 3^3 + ... +8100 * 3^n 
S(n) = 8100 * [ 1 + 3 + 3^2 + 3^3 + ... + 3^n ] 
and we know that : 
1 + 3 + 3^2 + 3^3 + ... + 3^n = (3^(n+1) - 1)/(3 - 1) 
= (3^(n+1) - 1)/2 
therefore 
S(n) = 8100 * (3^(n+1) - 1)/2 
finally : 
S(n) = 4050 * (3^(n+1) - 1) 
and this allows you to obtain the month n, if you know S(n) : 
3^(n+1) = S(n) /4050 + 1 
therefore : 

n = ln[S(n) /4050 + 1] /ln3 - 1 

hope it' ll help !!

Are you in plato my brudda it will be ok

Byou start by adding them all and setting them equal to 180 since that is half of the total degrees in a circle.(2x+8) + (3x-14) + (3x-14) = 1808x-20 = 1808x = 200x = 25