Asample of 4 different calculators is randomly selected from a group containing 46 that are defective and 26 that have no defects. what is the probability that all four of the calculators selected are defective? round to four decimal places.
a. 0.1666
b. 10.9154
c. 0.1586
d. 0.1021

Option 'c' is correct.

Step-by-step explanation:

Since we have given that

Number of defective calculators = 46

Number of non defective calculators = 26

Total number of calculators is given by

According to question,

Number of calculators is randomly selected = 4

So, Probability that all four of the calculators selected are defective is given by

Hence, Option 'c' is correct.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

a

b

d

step-by-step explanation: