The function f(x) is to be graphed on a coordinate plane
at what point should an open circle be drawn?
(–1, 0)
(0, 0)
(0, 1)
(1, 0)

-x, x< 0
1, x≥0

answer with real answer will mark brainliest if correct

The point where the open circle can be drawn on the graph of the function f(x) is:

               (0,0)

The function f(x) is given by:

           f(x)=  -x  when x < 0

            and    1  when x ≥ 0

The graph of the function f(x) is a line with a negative slope in the region x<0

and is a straight line parallel to the x-axis in the region x ≥ 0.

We know that in a graph of the function f(x) the open circle is drawn at the point where the inequality is strict i.e. that x is close to some value but could not be equal to that value.

Here x < 0

This means that x is close to zero but does not take the value 0.

Also, when  x is close to zero then f(x)= -0=0

Hence, the open circle is at (0,0)

well we know there are 4 clubs in 52 cards so it’s replaced so it should be 3/51

step-by-step explanation:

10 down (bang1)

5 up

5down (2)

2.5 up

2.5 down (3)

1.25 up

1.25 down (4)

now add them up : )

hoped i lol