You can stuff envelopes twice as fast as your friend. together, you can stuff 6750 envelopes in 4.5 hours. how long would it take for each of you working alone to complete the job individually?

Step-by-step explanation:

First, we have to find the individual ratio, how many envelopes per hour they can stuff.

So, we now that you can stuff envelopes twice faster than your friend, and both of you, that is, the sum, results in 6750 envelopes in 4.5 hours. The equation would be:

Now we apply the rule of three to find the time to stuff 6750 envelopes.

If your friend can stuff 500 envelopes per hour, how much time would take 6750?

So, it would take 13.5 hours to your friend, to stuff all envelopes alone.

Now, if you can envelope 1000 envelopes per hour, that is, twice than your friend. How much time would take to you to stuff 6750 envelopes?

It would take to you 6.75 hours to stuff all 6750 envelopes alone.

Therefore, the answers are 13.5 hours to your friend, and 6.75 to you.

it's d

step-by-step explanation:

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)