What are the zeros of the quadratic function f(x) = 6x2 + 12x – 7?

x = –1 – and x = –1 +
x = –1 – and x = –1 +
x = –1 – and x = –1 +
x = –1 – and x = –1 +

we have

To find the zeros equate the function to zero

Group terms that contain the same variable, and move the constant to the opposite side of the equation

Factor the leading coefficient

Complete the square. Remember to balance the equation by adding the same constants to each side

Rewrite as perfect squares

square root both sides

therefore

the answer is

The zeros of the quadratic function are

and

, .

Step-by-step explanation:

The given quadratic equation function is f(x) = 6x²+12x -7

To find the zeros of the quadratic equation we rewrite the function as

6x² + 12x - 7 = 0

Now we know the quadratic formula to get the solutions as

here a = 6

b = 12

c = -7

By putting these values in the formula

and

i think it is everything has to equal 180 so, if i correct 4=c. 6=d. 8=a. 7=b. and the last question would be c. because they are parallel lines and they are congruent.

step-by-step explanation:

the reason everything has to equal to 180 is because that is how it works. i'm guessing that is its rule. 4 and 8 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 6 and 7 are congruent and parallel so, that would be 30+30 because they have the same number. it would equal 60. 60+60 is 180. so, now you have your answer

answer

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step-by-step explanation: