Tan13pi/4 a. use the fact that there are 2pi radians in each circle to find another angle, smaller than 2 pi, that is equivalent to 13pi/4. b. find the tangent of the angle you found in part a. this is also 13pi/4.

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Step-by-step explanation:

Tan 13π/4 = tan(3π + 1/4π)

According to the trigonometry identity;

tan(A+B) = tanA + tanB/1-tanAtanB

If A = 3π and B = π/4

tan(3π + 1/4π) = tan 3π + tanπ/4/1-tan3πtanπ/4

If πrad = 180°

tan(3π + 1/4π) = tan 540° + tan45°/1-tan540°tan45°

tan(3π + 1/4π) = 0+1/1-0(1)

tan(3π + 1/4π) = 1/1-0

tan(3π + 1/4π) = 1/1

tan(3π + 1/4π) = 1

tan 13π/4 = 1

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.