Astudent government organization is selling christmas trees as a fundraiser. on friday, they sold 5 noble fir trees and 3 douglas fir trees for a total of $420. on saturday, 12 noble fir trees and 9 douglas fir trees were sold for a total of $1,080. what is the cost per tree for each type?
multiply the second equation by-3
N=60 noble fir trees
Solve for d
D=40 douglas fir trees
48/40 = 1 8/40
1 8/40 Simplify to 1 1/5
Hope this helps!
Answers:k = 13The smallest zero or root is x = -10
note: you can write "x^2" to mean "x squared"
f(x) = x^2+3x-10
f(x+5) = (x+5)^2+3(x+5)-10 ... replace every x with x+5
f(x+5) = (x^2+10x+25)+3(x+5)-10
f(x+5) = x^2+10x+25+3x+15-10
f(x+5) = x^2+13x+30
Compare this with x^2+kx+30 and we see that k = 13
Factor and solve the equation below
x^2+13x+30 = 0
(x+10)(x+3) = 0
x+10 = 0 or x+3 = 0
x = -10 or x = -3
The smallest zero is x = -10 as its the left-most value on a number line.