Determine the equation of the line with slope 3 that passes through the point (2, 0). y = −3x + 6 y = −3x − 6 y = 3x − 6 6x + 2y = 3

Y=mx+b where m=slope=(y2-y1)/(x2-x1) and b=y-intercept (value of y when x=0)

we are given that m=3 so

y=3x+b, using point (2,0) we can now solve for b

0=3(2)+b

0=6+b

-6=b so

y=3x-6