Trapezoid abcd is graphed in a coordinate plane.

what is the area of the trapezoid?

10 square units
12 square units
20 square units
24 square units

The area of ABCD is 12 square units. Option b is correct.

Step-by-step explanation:

From the given figure it is clear that the vertices of triangle are A(-5,-2), B(-1,2), C(0,-1), D(-2,-3).

The area of ABCD is the sum of area of triangle ABC and ACD.

Area of a triangle is

Area of triangle ABC is

The area of triangle ABC is 8 square units.

Area of triangle ACD is

The area of triangle ABC is 4 square units.

The are of ABCD is

Therefore the area of ABCD is 12 square units. Option b is correct.

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2