Find y such that the distance from (3,y) to (-1,2) is sqrt(65)

You're right - you use the distance formula for this. . You know one point, the x-coordinate of the other point, and the distance between the two points. When you plug this information into the equation, you get . To get rid of the square root, sqare both sides to get . Work out the subtraction in the parentheses and then square the answers to get: . Move the 25 over to get . Factor this out to get . Your two points are (2,-6) and (2,4).
Answer by rapaljer(4670)   (Show Source):You can put this solution on YOUR website!
The points you need to find are (2, y) such that the distance from (2,y) to (-2, -1) is 5. You are right to use the distance formula!! 
 
Square both sides of the equation:

 
 or 
y=3-1; or y = -3 -1
y = 2 or y = -4 

The points are (2,2) and (2, -4). 

Check: Distance from (2,2) to (-2, -1) = 
Distance from (2,-4) to (-2, -1) =  

R^2 at SCC