The volume of a cylindrical can is 15.7 in.3. the diameter is 2 in. find the height. use π = 3.14.

5 inches.

Step-by-step explanation:

hello

assuming the can is perfectly cylindrical, as a circle as base, the volume of the  cylinder is

where b is the base and h is the height

Now, b is the area of the circle

replacing in the volume equation

Step 1

isolate height from this equation , h is the unknown data

Step 2

put the values into the equation

Let

π = 3.14.

V= 15.7 cubic inches

Diameter= 2 inch

we need the radius,so

put the values into the equation

the height is 5 inches

Have a great day.

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}

i pretty sure it is