What is the reflection of image p(0,0) after two reflections first across x=-3 and
then across y=-3

P (0, 0) across x = -3 will change the x value. From 0 to -3 which is 3 units down, so the reflection will be another 3 units down ( points are the same distance from the reflection line) so the new x-value is -6 now just do the same thing for the y-value and you will get an image of P¹ ( -6, -6 )