Mathematics
Mathematics, 31.08.2019 15:30, anabelleacunamu

Ihave and for any value of c, a solution of the equation is and i am supposed to find the value of c for which y(3)=1. what i did was i took the differential of the first equation to get y' and substituted it in the second equation, along with the value for x (which is 3), to solve for c but when i put the value i got for c and the value of x into the first equation, i don't get y = 1. could anyone me see what i'm doing wrong?

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